pg_field_table
(PHP 5 >= 5.2.0, PHP 7, PHP 8)
pg_field_table — Returns the name or oid of the tables field
說明
pg_field_table() returns the name of the table that field
belongs to, or the table's oid if oid_only is true.
參數
-
result -
An PgSql\Result instance, returned by pg_query(), pg_query_params() or pg_execute()(among others).
-
field -
Field number, starting from 0.
-
oid_only -
By default the tables name that field belongs to is returned but if
oid_onlyis set totrue, then the oid will instead be returned.
返回值
On success either the fields table name or oid, 或者在失敗時返回 false.
更新日誌
| 版本 | 說明 |
|---|---|
| 8.1.0 |
現在 result 參數接受 PgSql\Result
實例，之前接受 資源(resource)。
|
範例
示例 #1 Getting table information about a field
<?php
$dbconn = pg_connect("dbname=publisher") or die("Could not connect");
$res = pg_query($dbconn, "SELECT bar FROM foo");
echo pg_field_table($res, 0);
echo pg_field_table($res, 0, true);
$res = pg_query($dbconn, "SELECT version()");
var_dump(pg_field_table($res, 0));
?>
以上例程的輸出類似於：
foo 14379580 bool(false)
註釋
注意:
Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.