Ds\Set::xor
(PECL ds >= 1.0.0)
Ds\Set::xor — Creates a new set using values in either the current instance or in another set, but not in both
說明
Creates a new set containing values in the current instance as well as another set
,
but not in both.
A ⊖ B = {x : x ∈ (A \ B) ∪ (B \ A)}
參數
-
set
-
The other set.
返回值
A new set containing values in the current instance as well as another set
,
but not in both.
範例
示例 #1 Ds\Set::xor() example
<?php
$a = new \Ds\Set([1, 2, 3]);
$b = new \Ds\Set([3, 4, 5]);
var_dump($a->xor($b));
?>
以上例程的輸出類似於:
object(Ds\Set)#3 (4) { [0]=> int(1) [1]=> int(2) [2]=> int(4) [3]=> int(5) }